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Voltage Divider Calculator

Vout from two resistors, or the resistors for the Vout you need.

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Two resistors in series divide a voltage (in the UK and India it's often called a potential divider). Enter the input voltage and both resistors to get the output voltage, the current and the power in each resistor.

Or work backwards: enter the voltage you need, for example 5 V down to 3.3 V for an ESP32 pin, and get standard resistor pairs ranked by accuracy.

How to use

  1. Enter Vin and the resistors R1 (between the input and the output) and R2 (between the output and ground).
  2. Read Vout, the current and the power in each resistor.
  3. Under Find resistors for a voltage, enter the voltage you need and pick the series. The total resistance range keeps the current low without making the output too weak.
  4. Tap a result to load it into the calculator above.

Voltage divider formula

Vout = Vin × R2 ÷ (R1 + R2). With 10 kΩ and 10 kΩ, the output is half the input. With R1 = 5.1 kΩ and R2 = 10 kΩ, 5 V becomes 3.31 V.

When not to use a divider

A divider only works with light loads: whatever you connect to the output acts as a resistor in parallel with R2 and pulls the voltage down. It's fine for reading a sensor or shifting a logic level; to power a circuit, use a voltage regulator.

Frequently asked questions

How do I get 3.3 V from 5 V with resistors?

Use R1 = 5.1 kΩ and R2 = 10 kΩ (E24 series), which gives 3.31 V. With E12 resistors, 1.2 kΩ and 2.2 kΩ give 3.24 V.

What resistor values should I use?

Between 1 kΩ and 100 kΩ in total for most circuits. Lower values waste current; very high values make the output sensitive to noise and to the load.

Can I power something from a voltage divider?

Not really: the voltage drops as soon as you draw current. To power a circuit, use a regulator such as an LM7805 or an AMS1117.

How do I measure a 12 V battery with an Arduino?

Use a divider that brings the highest battery voltage below the board's reference (5 V or 3.3 V) and connect the output to an analog pin. On a 5 V board, 10 kΩ and 4.7 kΩ give 3.84 V at 12 V, leaving headroom up to about 15 V.

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